2x-y-45=0 x-2y+21=0 what is is the solution by using substitution method
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Answered by
0
x - 2y + 21 = 0
2x - y = 45
y = 2x - 45
As, x - 2y = -21
x - 2(2x-45) = -21
x - 4x + 90 = -21
-3x = -111
x = 37
y = 2x - 45 = 2(37) - 45 = 29
2x - y = 45
y = 2x - 45
As, x - 2y = -21
x - 2(2x-45) = -21
x - 4x + 90 = -21
-3x = -111
x = 37
y = 2x - 45 = 2(37) - 45 = 29
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Answered by
1
2x-y-45 = 0 → (1)
x-2y+21=0 → (2)
frm (2)
x = 2y-21
substituting x in (1)
2(2y-21)-y-45 =0
4y-42-y-45 =0
3y-87=0
y=29
∴x = 2*29 -21
= 37
Hope it helps..... :)
x-2y+21=0 → (2)
frm (2)
x = 2y-21
substituting x in (1)
2(2y-21)-y-45 =0
4y-42-y-45 =0
3y-87=0
y=29
∴x = 2*29 -21
= 37
Hope it helps..... :)
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