Math, asked by sainavin2076, 10 months ago

2x+y-5=0;3x+2y-8=0 SOLVE BY CROSS MULTIPLICATION METHOD.

Answers

Answered by MaheswariS
0

\underline{\textbf{Given:}}

\mathsf{2\,x+y-5=0\;\;and\;\;3\,x+2\,y-8=0}

\underline{\textbf{To find:}}

\textsf{Solution of the given equations by Cross multiplication}

\mathsf{method}

\underline{\textbf{Solution:}}

\mathsf{Consider,}

\mathsf{2\,x+y-5=0\;\;and\;\;3\,x+2\,y-8=0}

\textsf{By Cross multiplication method,}

\mathsf{\dfrac{x}{1(-8)-2(-5)}=\dfrac{y}{3(-5)-2(-8)}=\dfrac{1}{2(2)-1(3)}}

\mathsf{\dfrac{x}{-8+10}=\dfrac{y}{-15+16}=\dfrac{1}{4-3}}

\mathsf{\dfrac{x}{2}=\dfrac{y}{1}=\dfrac{1}{1}}

\mathsf{\dfrac{x}{2}=\dfrac{y}{1}=1}

\implies\mathsf{\dfrac{x}{2}=1\;\;\;\;\;\&\;\;\;\;\;\dfrac{y}{1}=1}

\implies\mathsf{x=2\;\;\;\;\;\&\;\;\;\;\;y=1}

\therefore\textbf{Solution is x=2 and y=1}

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