Math, asked by Rakshitakurahatti, 4 months ago

2x - Y-5= 0 and
x + y -7=0
Draw a
graph to the linear equation.​

Answers

Answered by mathdude500
16

\large\underline{\sf{Solution-}}

Given equation of lines are

\rm :\longmapsto\:2x - y - 5 = 0

and

\rm :\longmapsto\:x  + y - 7 = 0

can be rewritten as

\rm :\longmapsto\:2x - y = 5

and

\rm :\longmapsto\:x  +  y = 7

Now, Consider

\rm :\longmapsto\:2x - y = 5

Substituting 'x = 0' in the given equation, we get

\rm :\longmapsto\:2(0) - y = 5

\rm :\longmapsto\:0 - y = 5

\rm :\longmapsto\: - y = 5

\rm :\longmapsto\: y = -  \:  5

Substituting 'y = 0' in the given equation, we get

\rm :\longmapsto\:2x - 0= 5

\rm :\longmapsto\:2x = 5

\rm :\longmapsto\:x = 2.5

Hᴇɴᴄᴇ,

➢ Pair of points of the given equation are shown in the below table.

\begin{gathered}\boxed{\begin{array}{c|c} \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 0 & \sf  - 5 \\ \\ \sf 2.5 & \sf 0 \end{array}} \\ \end{gathered}

➢ Now draw a graph using the points (0 , - 5) & (2.5 , 0)

➢ See the attachment graph.

Consider Line

\rm :\longmapsto\:x  +  y = 7

Substituting 'x = 0' in the given equation, we get

\rm :\longmapsto\:0  +  y = 7

\rm :\longmapsto\:y = 7

Substituting 'y = 0' in the given equation, we get

\rm :\longmapsto\:x  +  0 = 7

\rm :\longmapsto\:x = 7

Hᴇɴᴄᴇ,

➢ Pair of points of the given equation are shown in the below table.

\begin{gathered}\boxed{\begin{array}{c|c} \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 0 & \sf  7 \\ \\ \sf 7 & \sf 0 \end{array}} \\ \end{gathered}

➢ Now draw a graph using the points (0 , 7) & (7 , 0)

➢ See the attachment graph.

Attachments:
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