Question

2x-y=5;3×+2y=11 by elimination method​

Answer 1

Step-by-step explanation:

x=3 ,,,y= 1 is a answer of the question

Answer 2

Given

• Two equations :-
• 2x - y = 5
• 3x + 2y = 11

To find

• The value of x and y by elimination method

Solution

We are given two equations and we have to find the values of x and y by elimination method.

Elimination method :-

• Firstly, we make one of the variable same in this equation
• Then we make the signs of the variables opposite to each other. So, that the variables gets cancelled.
• Then we get the value of one on the variable from there we can find thr value of the other variable by substituting the value of variable we have found in any of the one equation.

Let's solve :-

❖ 2x - y = 5 ---(1)

❖ 3x + 2y = 11 ----(2)

We will make any one of the variable's value same.

[2x - y = 5] × 2

[3x + 2y = 12] × 1

⟶ 4x - 2y = 10

⟶ 3x + 2y = 12

We will cancel - 2y and + 2y as both of them are having opposite signs.

4x - 2y = 10

3x + 2y = 12

____________

7x = 22

____________

• 7x = 22

⟶ x = 22/7

⟶ x = 3.14 ----(3)

Substituting (3) in (1)

2x - y = 5

⟶ 2(3.14) - y = 5

⟶ 6.28 - y = 5

⟶ - y = 5 - 6.28

⟶ - y = - 1.28

⟶ y = 1.28

Therefore, the value of x and y :-

• x = 3.14
• y = 1.28

_______________________________

Verification :-

Substitute the value of x and y in equation (1)

⟶ 2x - y = 5

LHS

⟶ 2 × 3.14 - 1.28

⟶ 6.28 - 1.28

⟶ 5

• 5 = 5

LHS = RHS

Hence, verified.