Question

2x+y=5 3x+2y=8 in elimation method​

Answer 1

Answer:

x=2, y=1

Step-by-step explanation:

2x+y=5 ----(1)

3x+2y=8--------(2)

eq(1)*2 -----2(2x+y=5)

by elimination method

4x+2y=10

3x+2y=8

- - -

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x=2

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sub x=2in eq1

2(2)+y=5

4+y=5

y=1

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Answer 2

(2x+y=5)3. (3x+2y=8)2. Now we will get as 6x+3y=15–eq1. 6x+4y=16—eq2. Here let us substract (eq1—eq2) in this 6x;6x will get cancelled then we get y=1 and let us keep this y in equation 2x+y=5 then we get value of x as 2. So,we get y=1 and x=2