Question

2x+y=5; 3x-y=5, Solve the set of simultaneous equations.

Answer 1

2x + y = 5 -------(1)

3x - y = 5 -------(2)

On adding equation 1 and 2, we get

5x = 10

=> x = 2

Now,

On substituting the value of x in equation 1, we get

2(2) + y = 5

=> y = 5 - 4

=> y = 1

Answer 2

Answer:

On solving equations simultaneously we get , value of $x = 2$ and $y = 1$ .

Step-by-step explanation:

To solve : simultaneous equations.

Given equations : $2x+y=5$ -----------(i)

                              $3x-y=5$ ----------(ii)

Solution :

• To solve given equations simultaneously  we multiply equation (i) by $3$ and equation (ii) by $2$ to equalize coefficients of $x$ .
• On multiplying  ( $2x+y=5$  ) by $3$ we get ,

         $6x + 3y = 15$    ---------------------(iv)

• On multiplying  (  $3x-y=5$  ) by $2$ we get ,

         $6x -2y = 10$   ---------------------(v)

• Now , subtracting (v) from (iv) we get ,
• ( $6x + 3y = 15$ ) - ( $6x -2y = 10$ )
• On subtracting LHS of both equations we get , $5y$
• On subtracting RHS of both equations we get , 5
• Resultant equation becomes , $5y = 5$
• We get ,value of  $y = \frac{5}{5}$

                                    $y =1$

• Now , substituting value of $y$ in (i) ,
• $2x+y=5$

        $2x + (1) = 5\\\\2x = 4 \\\\x = 2$