2x + y = 7
3x + 2y = 11
Answers
Answered by
3
multiplying equation (1) by 2
we get 4x+2y=14
and. 3x+2y=11
.........- ...- .....-. (by subtracting)
________
x=3
and y=1
we get 4x+2y=14
and. 3x+2y=11
.........- ...- .....-. (by subtracting)
________
x=3
and y=1
saba659:
Friend ur answer is correct but I didn't understand ur explanation please explain me one more time
Then x = 7 - y/2 ---- (1)
Given 3x + 2y = 11
3(7 - y)/2 + 2y = 11
21 - 3y + 4y = 22
21 + y = 22
y = 1
Substitute y = 1 in (1), we get
x = 7 - 1/(2)
= 6/2
= 3
Answered by
2
Given equation are 2x + y = 7
x = 7 - y/2 ------- (1)
Given 3x + 2y = 11 ----- (2)
Substitute (1) in (2), we get
3(7 - y/2) + 2y = 11
21 - 3y + 4y = 22
21 + y = 22
y = 22 - 21
y = 1. ------- (3)
Substitute (3) in (2), we get
3x + 2y = 11
3x + 2 = 11
3x = 11 - 2
3x = 9
x = 9/3
x = 3.
Therefore the required solutions are x = 3 and y = 1.
Hope this helps!
x = 7 - y/2 ------- (1)
Given 3x + 2y = 11 ----- (2)
Substitute (1) in (2), we get
3(7 - y/2) + 2y = 11
21 - 3y + 4y = 22
21 + y = 22
y = 22 - 21
y = 1. ------- (3)
Substitute (3) in (2), we get
3x + 2y = 11
3x + 2 = 11
3x = 11 - 2
3x = 9
x = 9/3
x = 3.
Therefore the required solutions are x = 3 and y = 1.
Hope this helps!
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