Question

2x+y=7 3x+2y=12 solve the pair of equation

Answer 1

Answer:

Refer to the attachment above

Answer 2

$\rm\huge\blue{\underline{\underline{ Question :}}}$

2x+y=7 3x+2y=12 solve the pair of equation.

$\rm\huge\blue{\underline{\underline{ Solution : }}}$

★ Given that,

• Solve the equations : 2x + y = 7, 3x + 2y = 12

★ To find,

• Values of x & y.

★ Let,

The equations be

$\sf\:\implies 2x + y = 7 ..... (1)$

$\sf\:\implies 3x + 2y = 12 ..... (2)$

• By using " Substitution Method " We can solve it.

We can write the equation (1) as,

$\sf\:\implies y = 7 - 2x ..... (3)$

• Substitute the value of y in (2)

$\sf\:\implies 3x + 2(7 - 2x) = 12$

$\sf\:\implies 3x + 14 - 4x = 12$

$\sf\:\implies 14 - x = 12$

$\sf\:\implies 14 - 12 = x$

$\sf\:\implies x = 2$

Hence,the value of x is 2.

• Substitute the value of x in (3).

$\sf\:\implies y = 7 - 2(2)$

$\sf\:\implies y = 7 - 4$

$\sf\:\implies y = 3$

★ Verification,

Put the values of x & y in (1) to prove LHS = RHS.

LHS = 2x + y

$\sf\:\implies 2(2) + 3$

$\sf\:\implies 4 + 3$

$\sf\:\implies 7$

Hence, LHS = RHS. Since, it was verified.

$\underline{\boxed{\bf{\purple{ \therefore x = 2 ; y = 3}}}}\:\orange{\bigstar}$

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