Math, asked by poojaS7072, 23 days ago

(2x - y) dx = (x-y) dy solve the differential equations ​

Answers

Answered by pulakmath007
12

SOLUTION

TO SOLVE

The differential equation

 \sf{(2x - y)dx = (x - y)dy}

EVALUATION

Here the given differential equation is

 \sf{(2x - y)dx = (x - y)dy}

We solve as below

 \sf{(2x - y)dx = (x - y)dy}

 \sf{ \implies \: 2x  \: dx- y \: dx = x  \: dy- y \: dy}

 \sf{ \implies \: 2x  \: dx- y \: dx  - x  \: dy +  y \: dy = 0}

 \sf{ \implies \: 2x  \: dx-( y \: dx   +  x  \: dy) +  y \: dy = 0}

 \sf{ \implies \: 2x  \: dx-d \: (x y ) +  y \: dy = 0}

On integration we get

  \displaystyle\sf{ \int 2x  \: dx- \int d \: (x y ) +  \int y \: dy = 0}

\displaystyle\sf{ \implies 2. \frac{ {x}^{2} }{2} - (x y ) +   \frac{ {y}^{2} }{2}  =  \frac{c}{2} }

\displaystyle\sf{ \implies 2 {x}^{2} - 2xy +  {y}^{2}    = c}

Where C is integration constant

FINAL ANSWER

Hence the required solution is

\boxed{ \:  \:   \displaystyle\sf{  2 {x}^{2}  -2 xy +  {y}^{2} = c} \:  \: }

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