(2x-y)whole sq -11(2x-y)+28
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Answered by
41
Hi ,
( 2x - y )² - 11( 2x - y ) + 28
Splitting the middle term , we get
= ( 2x - y )² - 7(2x - y ) - 4( 2x - y ) + 28
= ( 2x - y )[ 2x - y - 7 ] - 4[ 2x - y - 7 ]
= ( 2x - y - 7 ) ( 2x - y - 4 )
I hope this helps you.
: )
( 2x - y )² - 11( 2x - y ) + 28
Splitting the middle term , we get
= ( 2x - y )² - 7(2x - y ) - 4( 2x - y ) + 28
= ( 2x - y )[ 2x - y - 7 ] - 4[ 2x - y - 7 ]
= ( 2x - y - 7 ) ( 2x - y - 4 )
I hope this helps you.
: )
Answered by
12
Step-by-step explanation:
(2x-y)^2 -11(2x-y) + 28
(2x-y)^2 - 7(2x-y) - 4(2x-y) + 28
(2x-y) (2x-y-7) - 4 (2x-y-7)
(2x-y-7) (2x-y-4)
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