(2x - y) (x + y)2 + (2y - x)} DO FACTORISATION
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Answer:
(2x-y){(x+y)^2 + 1}
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Step-by-step explanation:
(2x - y)( x + y)2 + (2y - x) = 0
(2x - y)(x2 + 2xy +y2) + (2y - x) = 0
2x( x2 +2xy + y2 ) -y( x2 +2xy + y2 ) + (2y - x) = 0
2x3 + 4x2y + 2xy2 -x2y -2xy2 -y3 + 2y - x = 0
2x3 + 3x2y -y3+ 2y -x = 0
2x3 + 3x2y -y3 = x - 2y
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