Math, asked by chheduramchandrakar, 5 months ago

2x+y+z=10 3x+2y+3z=18 x+4y+9z=16​

Answers

Answered by anuj201251
2

Answer:

2x+y+z = 10. 3x+2y+3z = 18 x+4y+9z = 16. Solution. In the first stage, the multipliers are − 3/2 and −1/2. We multiply the first equation.

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