Question

(2x-y+z)² Algebric Identity​

Answer 1

Step-by-step explanation:

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Here is the answer you were looking for:

\begin{gathered}{(2x - y + z)}^{2} \\ \\ using \: the \: identity \\ {(a - b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} - 2ab - 2bc + 2ca \\ \\ = {(2x)}^{2} + {(y)}^{2} + {(z)}^{2} - 2 \times 2x \times y - 2 \times y \times z + 2 \times z \times 2x \\ \\ = 4 {x}^{2} + {y}^{2} + {z}^{2} - 4xy - 2yz + 4xz\end{gathered}

(2x−y+z)

2

usingtheidentity

(a−b+c)

2

=a

2

+b

2

+c

2

−2ab−2bc+2ca

=(2x)

2

+(y)

2

+(z)

2

−2×2x×y−2×y×z+2×z×2x

=4x

2

+y

2

+z

2

−4xy−2yz+4xz

Hope this helps!

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Answer 2

Answer:

(x+y+z)^2=x^2+y^2+z^2+2xy+2yz+2zx.