Math, asked by karuba143, 2 months ago

(2x-y+z)^2 expand the sum using suitable identites​

Answers

Answered by Priyaasha
2

Answer:

4x^2+y^2+z^2-4xy-2yz+4xz

Step-by-step explanation:

(2x-y+z)^2

using the identity => (a-b+c)^2

= a^2+b^2+c^2-2ab-2bc+2ca

=> (2x)^2 + (y)^2+(z)^2-2×2x×y-2×y×z+2×z×2x

=> 4x^2+ y^2+z^2-4xy-2yz+4xz

hope you understand...

Answered by prarthana200749
1

Answer:

4x^2+y^2+z^2-4xy-2yz+4xz

Step-by-step explanation:

Its in the form of

(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca

(2x-y+z)^2=(2x)^2+(-y)^2+(z)^2+2(2x)(-y)+2(-y)(z)+2(z)(2x)

(2x-y+z)^2=4x^2+y^2+z^2-2xy-2yz+4xz

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