Question

(2x-y-z)^2 expand using identity

Answer 1

$hi \: ...$

here is your answer ....

To expand :

$( {2x - y - z})^{2}$

By using formula ...

$( {a + b + c})^{2} = {a}^{2} + {b}^{2} + {c}^{2} \\ + 2ab + 2bc + 2ac$

Thus ,

$( {2x - y - z})^{2}$

$=( {2x})^{2} + ({ - y})^{2} + ( { - z})^{2} \\ + 2(2x)( - y) + 2( - y)( - z) \\ + 2(2x)( - z)$

$= 4 {x}^{2} + {y}^{2} + {z}^{2} - 4xy + \\ 2yz - 4xz$

hope this helps ! ! !

Answer 2

✨✨✨✨✨

(2x-y-z)²

= (2x)² + y² + z² - 2.2x.y + 2.y.z - 2.z.2x

= 4x² + y² + z² - 4xy + 2yz - 4xz

[by using the identity (a-b-c)² = a² + b² + c² - 2ab + 2bc - 2ca]

Hope this helps you friend.....

✨✨✨ Be brainly ✨✨✨