Math, asked by deep255, 1 year ago

(2x-y+z)² expand using suitable identity

Answers

Answered by DaIncredible
1088
Hey friend,
Here is the answer you were looking for:
 {(2x - y + z)}^{2}   \\  \\ using \: the \: identity \\  {(a - b + c)}^{2}  =  {a}^{2}  +  {b}^{2}  +  {c}^{2}   - 2ab - 2bc + 2ca \\  \\  =  {(2x)}^{2}  +  {(y)}^{2}  +  {(z)}^{2}  - 2 \times 2x \times y - 2 \times y \times z + 2 \times z \times 2x \\  \\  = 4 {x}^{2}  +  {y}^{2}  +  {z}^{2}  - 4xy - 2yz + 4xz

Hope this helps!!!!

@Mahak24

Thanks...
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deep255: thanks
DaIncredible: my pleasure
deep255: thanks
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Answered by mysticd
484
Hi ,

***********************

We know the algebraic identity ,

( a + b + c )² = a²+b²+c²+2ab+2bc+2ca

*********************************

Here ,

a = 2x,

b = - y ,

c = z ,

[ 2x + ( -y ) + z ]²

= (2x)²+(-y)²+z²+2(2x)(-y)+2(-y)z+2z(2x)

= 4x² + y² + z² - 4xy - 2yz + 4zx

I hope this helps you.

: )
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