Question

(2x-y+z)² expand using suitable identity

Answer 1

Hey friend,
Here is the answer you were looking for:
${(2x - y + z)}^{2} \\ \\ using \: the \: identity \\ {(a - b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} - 2ab - 2bc + 2ca \\ \\ = {(2x)}^{2} + {(y)}^{2} + {(z)}^{2} - 2 \times 2x \times y - 2 \times y \times z + 2 \times z \times 2x \\ \\ = 4 {x}^{2} + {y}^{2} + {z}^{2} - 4xy - 2yz + 4xz$

Hope this helps!!!!

@Mahak24

Thanks...
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Answer 2

Hi ,

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We know the algebraic identity ,

( a + b + c )² = a²+b²+c²+2ab+2bc+2ca

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Here ,

a = 2x,

b = - y ,

c = z ,

[ 2x + ( -y ) + z ]²

= (2x)²+(-y)²+z²+2(2x)(-y)+2(-y)z+2z(2x)

= 4x² + y² + z² - 4xy - 2yz + 4zx

I hope this helps you.

: )