Math, asked by vaibhavmalhotra5206, 11 months ago

(2x-y-z)3+(2y-z-x)3+(2z-x-y)3

Answers

Answered by unnati824
1

Answer:

(2x-y-z)+(2y-z-x)+(2z-x-y)

=2x-y-z+2y-z-x+2z-x-y

=0

When a+b+c =0 , then a^3+b^3+c^3=3abc

•°• ,(2x-y-z)^3+(2y-z-x)^3+(2z-x-y)^3

=3(2x-y-z)(2y-z-x)(2z-x-y)

(No Need to Expand)

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