Math, asked by ankittri, 6 months ago

(2x-y-z)3+(2y-z-x)3+(3z-x
-y)​

Answers

Answered by Anonymous
9

Solution :-

→ ( 2x - y - z) 3 + ( 2y - z - x ) 3 + ( 3z - x - y )

→ 6x - 3y - 3z + 6y - 3z - 3x + 3z - x - y

→ 6x - 3x - x - 3y + 6y - y - 3z - 3z + 3z

→ 2z + 2y - 3z

Answered by Anonymous
18

\huge\star\underbrace {\mathtt\purple {A}\mathtt\purple {n}\mathtt\purple {s}\mathtt\purple {w}\mathtt\purple {e}\mathtt\purple {r}}\star\:

( 2x - y - z) 3 + ( 2y - z - x ) 3 + ( 3z - x - y )

6x - 3y - 3z + 6y - 3z - 3x + 3z - x - y

6x - 3x - x - 3y + 6y - y - 3z - 3z + 3z

2z + 2y - 3z

Similar questions