2x° and 60° are interior angle. then find x.
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Given angle of pentagon are x,x+20,x+40,x+60 and x+80
We know that sum of angle of pentagon =5400
Then x+x+20+x+40+x+60+x+80=540
⇒5x+200=540
⇒5x=540−200
⇒x=5340=68o
Then smallest angle of pentagon is 68o
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the above answer is correct dear friend
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