Question

2x² - 10x + 12


Plzzz answer it!!!!​

Answer 1

Given equation

$2x^{2} -10x+12=0$

Solving, we get,

$2x^{2} -10x+12=0$

$\implies 2x^{2} -4x-6x+12=0$

$\implies 2x(x-2)-6(x-2)=0$

$\implies (2x-6)(x-2)=0$

$\implies 2(x-3)(x-2)=0$

$\implies (x-3)(x-2)=0$

Now,

$x-3=0\\\implies x = 3$

$x-2=0\\\implies x = 2$

$\boxed{\boxed{\bold{Therefore, \ the \ zeroes \ of \ the \ polynomial \ are \ 3 \ and \ 2 \ respectively}}}}}$

                                                     

Answer 2

$\huge\mathfrak{Answer:}$

Given:

• We have been given a quadratic polynomial 2x² - 10x + 12.

To Find:

• We need to find the zeroes of this polynomial.

Solution:

The given polynomial is 2x² - 10x + 12.

We can find the zeroes of this polynomial by the method of splitting the middle term.

We need to find two such numbers whose sum is -10 and product is 24.

Two such numbers are -4 and -6.

Substituting the values, we have

2x² - 4x - 6x + 12 = 0

=> 2x(x - 2) -6(x - 2) = 0

=> (x - 2)(2x - 6) = 0

Either (x - 2) = 0 or (2x - 6) = 0.

When (x - 2) = 0

=> x = 2

When (2x - 6) = 0

=> 2x = 6

=> x = 6/2

=> x = 3

Hence, two zeroes of this polynomial are 2 and 3.