Question

2x²+11x+12
Please
By splitting middle term.. ​

Answer 1

Given :-

$2 {x}^{2} + 11x + 12 = 0$

What to find out =Roots of the equation?

Solution :-

Factorise by splitting middle term

$2 {x}^{2} + 11x + 12 = 0 \\ \\ 2 {x}^{2} + 8x + 3x + 12 = 0 \\ \\ 2x(x + 4) + 3(x + 4) = 0 \\ \\ (x + 4)(2x + 3) = 0$

Now split it into possible cases

$(x +4 ) = 0 \\ \\ \\ (2x + 3) = 0$

Hence,

$x_1 = ( - 4) \\ \\ x_2 =( - \frac{3}{2} )$

Extra information :-

• A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared. The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable.

Answer 2

Answer:

(x+6)(2x-2)

Explanation:

In order to factorize, we 2x²+11x+12 have to find two numbers p and q such that p+q = 11 and pq=12.

Clearly 12 - 1 = 11 and 12 × 1 = 12

We will now split the middle term 11x of 2x²+11x+12 as 12x-x, so that,

2x²+12x-x+12

= 2x(x+6)-2(x+6)

= (x+6)(2x-2)

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