Question

2x2-12x+18=0
$2 {x}^{2} - 12x + 18 = 0$

Answer 1

2x^2 - 12x + 18 = 0

=> x^2 - 6x + 9 = 0

=> x^2 - 3x - 3x + 9 = 0

=> x ( x - 3) - 3(x - 3) = 0

=> (x - 3)(x - 3) = 0

x = 3 and 3

Answer 2

HEY MATE ..……
HERE IS YOUR ANSWER.……
$2 {x}^{2} - 12x + 18 = 0 \\ 2 {x}^{2} - 12x = 0 - 18 \\ 2 {x}^{2} - 12x = - 18 \\ {x}^{2} - 12x \: \: = \frac{ - 18}{2} \\ {x}^{2} - 12x \: \: = - 9 \\ x \:\: \: - 12x \: = \sqrt{ - 9} \\ 11x = - 3 \\ x \: \: \: = \frac{ - 3}{11}$

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