Question

2x²- 15 x + 25=0
middle term splitting

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Answer 1

Answer:

2x²-(10x+5x)+25=0

2x²-10x-5x+25=0

2x(x-5)-5(x-5)=0

(2x-5)(x-5)=0

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Answer 2

${Solution}$

Given to split the middle term :-

2x² - 15x + 25 = 0

Solution :-

We have to split the middle term Here 2x² - 15x + 25 = 0

Product of two numbers should be 50x² And their sum should be equal to 15x

Finding factors :-

1x × 50x = 50x² or you can keep - for all

2x × 25x = 50x²

5x × 10x = 50x²

10x × 5x = 50x²

If you observe these Sum of two numbers is 15x and product should be 50x²

-5x -10x = 15x ; -5x × -10x = 50x²

So, split the middle term as -5x - 10x (as - is there before)

___________________________

2x² - 15x + 25 = 0

2x² - 5x - 10x + 25 = 0

2x² - 10x - 5x + 25 = 0

2x (x -5) -5 (x -5) = 0

(x -5) (2x -5) = 0

Finding zeroes

x - 5 = 0

x = 5

2x - 5 = 0

2x = 5

x = 5/2

So, the values of x are 5, 5/2