Math, asked by Siakhan4995, 1 month ago

2x²-16-x²+2x-8=
دو ضربدر ایکس

Answers

Answered by shaileshtiwari81577

0

Answer:

$2x {}^{2} - 16x {}^{2} + 2x - 8$

$(2 - 16)x {}^{2} + 2x - 8$

$- 14x {}^{2} + 2x - 8$

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