2x²+16x
![2x {4} + 16x 2x {4} + 16x](https://tex.z-dn.net/?f=2x+%7B4%7D++%2B+16x)
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Answer:
Example 1.
2x2 - 5x - 12 = 0.
(2x + 3)(x - 4) = 0.
2x + 3 = 0 or x - 4 = 0.
x = -3/2, or x = 4.
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