2x²+2√2x+1 find roots of this equation
karneet:
like make x any random number and solve it?
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Answered by
1
A=2
B=2√2 = √8
C= 1
By, x=-b+/- √b^2-4ac/2a
X= -√8 +or - √(√8)^2-4*2*1/2*2
X=-√8 + or - √8-1/4
X= - √8 + or- √7/4
Therefore, roots are x= -√8+√7/4 and -√8-√7/4.
B=2√2 = √8
C= 1
By, x=-b+/- √b^2-4ac/2a
X= -√8 +or - √(√8)^2-4*2*1/2*2
X=-√8 + or - √8-1/4
X= - √8 + or- √7/4
Therefore, roots are x= -√8+√7/4 and -√8-√7/4.
Answered by
2
2x²+2√2x+1=0this is a perfect square,
(√2x+1)²=0
√2x+1=o
√2x=-1
x=-1/√2
(√2x+1)²=0
√2x+1=o
√2x=-1
x=-1/√2
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