Question

2x2-2√6x+3=0 find the nature of roots

Answer 1

Answer:

Here is your answer:

a=2,b=2√6,c=3

D=b^2-4ac

= 24 - 4*2*3

=24-24

=0

Hence, roots are equal.

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Answer 2

Given,

A quadratic equation: 2x2-2√6x+3=0

To find,

The nature of the roots.

Solution,

We can simply solve this mathematical problem using the following process:

Mathematically,

In a quadratic equation: ax^2 + bx + c = 0, the nature of its roots is determined by the value of discriminant D = (b^2-4ac), as follows:

a) if D>0, then real and distinct roots

b) if D=0, then real and equal roots

c) if D<0, then complex and distinct roots

Now, according to the question;

Discriminant value of the given quadratic equation

= D = b^2-4ac

= (-2√6)^2-4(2)(3)

= 4×6 - 4×6 = 0

=> D = 0

=> The given quadratic equation has two real and equal roots

Hence, both the roots of the given quadratic equation are real and equal.