Question

2x²-2√6x+3=0

x= 1/√3 Find the Roots

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Answer 1

Answer:

2x²-2√6x+3=0

2x²-√6x-√6x+3=0

√2x(√2x-√3)-√3(√2x-√3)=0

(√2x-√3)(√2x-√3)=0

x=√3/√2,√3/√2

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