Question

2x² + 20x + 50प्लीज गिव मी आंसर ​

Answer 1

Answer:

2x²+10x+10x+50

2x(x+5)+10(x+5)

(2x+10)(x+5)

Answer 2

$\huge\bold{\gray{\sf{Answer:}}}$

Explanation:

It is in the form of a quadratic equation$a {x}^{2} + bx + c$ so, we factorise it to find roots

How to factorise..??

step1: Multiply the constant term coefficient of x square.suppose we obtain 'z' after multiplying

step 2:Think of a number whose sum and product makes the 'z'

step 3: now split the middle term by that number which you think.

step 4:At last take common and compare with equal to 0 we obtain the roots .

$2 {x}^{2} + 20x + 50$

$= > 2 {x}^{2} + 10x + 10x + 50$

$= > 2 x(x + 5) + 10(x + 5) = 0$

$= > (2x + 10)(x + 5) = 0$

$2x + 10 = 0$

$= > x = \frac{ - 10}{2} = - 5$

$= > x + 5 = 0$

$x = - 5$

Therefore,roots are (-5,-5)