2x²-23x+63=0 solve
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Answered by
4
HELLO
HERE IS UR ANSWER,
2x- 23x + 63 = 0
(Write as a difference)
=> 2x- 9x - 14x +63 = 0
(Factor the expressions)
=> xx(2x-9) - 7(2x - 9) = 0
( Factor the expression)
=> (2x-9)x(x - 7) = 0
HOPE IT HELPS ✌
Answered by
2
2x^2-23x+63=0
Solve by splitting the middle term:
63*2=126
Here, the product is 126 and the sum should be -23
+126
/\
-9 -14 = -23
Now, div 9 /2 and 23/2
So, you will get,
(2x-9)(2x-23)=0
Therefore, x=9/2 or x=23/2
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