Question

2x2 - 272x+1 = 0 find roots​

Answer 1

♡ǫᴜᴇsᴛɪᴏɴ:

ғɪɴᴅ ᴛʜᴇ ʀᴏᴏᴛs ᴏғ ᴛʜᴇ ǫᴜᴀᴅʀᴀᴛɪᴄ ᴇǫᴜᴀᴛɪᴏɴ 2x²-272x+1=0.

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2x²-272x+1=0........(Given)

ᴄᴏᴍᴘᴀʀɪɴɢ ᴛʜᴇ ᴀʙᴏᴠᴇ ᴇǫᴜᴀᴛɪᴏɴ ᴡɪᴛʜ ax²+bx+c=0.

ᴛʜᴇʀᴇғᴏʀᴇ,

◆ a= 2

◆ b=-272

◆c=1

ɴᴏᴡ, ʟᴇᴛ's ғɪɴᴅ b²-4ac

: . b²-4ac=(-272) ²-4×2×1

= 73984-8

= 73976

By using the formula,

x= -b±√b²-4ac/2a

: . x= 272±√73976/2

: . x= 272+√73976/2 OR 272-√73976/2

: . x= 136+√73976 OR 136-√73976

sᴏ ᴛʜᴇ ʀᴏᴏᴛs ᴏғ ᴛʜᴇ ɢɪᴠᴇɴ ǫᴜᴀᴅʀᴀᴛɪᴄ ᴇǫᴜᴀᴛɪᴏɴ ᴀʀᴇ (136+√74976 , 136-√74976)

Answer 2

Answer:

2x²-272x+1=0........(Given)

ᴄᴏᴍᴘᴀʀɪɴɢ ᴛʜᴇ ᴀʙᴏᴠᴇ ᴇǫᴜᴀᴛɪᴏɴ ᴡɪᴛʜ ax²+bx+c=0.

ᴛʜᴇʀᴇғᴏʀᴇ,

◆ a= 2

◆ b=-272

◆c=1

ɴᴏᴡ, ʟᴇᴛ's ғɪɴᴅ b²-4ac

: . b²-4ac=(-272) ²-4×2×1

= 73984-8

= 73976

By using the formula,

x= -b±√b²-4ac/2a

: . x= 272±√73976/2

: . x= 272+√73976/2 OR 272-√73976/2

: . x= 136+√73976 OR 136-√73976

sᴏ ᴛʜᴇ ʀᴏᴏᴛs ᴏғ ᴛʜᴇ ɢɪᴠᴇɴ ǫᴜᴀᴅʀᴀᴛɪᴄ ᴇǫᴜᴀᴛɪᴏɴ ᴀʀᴇ (136+√74976 , 136-√74976)