Question

2x² + 2xy - y²= 0 seperate equation
​

Answer 1

Step-by-step explanation:

The factors of the equation x2+2xy−y2=0 by the discriminant method are,

x=2−2y±(2y)2−4(−y2)

=2−2y±22y

=−y±2y

x=−y(1+2),x=y(2−1)

x+(1+2)y=0,x−(2−1)y=0

Therefore, the separate equations of lines are x+(1+2)y=0 and x−(2−1)y=0.