Question

2x²-3√2+2=0 please answer​

Answer 1

Answer:

3√2x²-5x-√2=0

3√2x²-(6-1)x -√2 = 0

3√2x²- 6x + x-√2=0

3√2x(x-√2)+1(x-√2) = 0

(x-√2)(3√2x+1) = 0

.•. x=√2 or x = -1/3√2

so the roots are √2 & -1/3√2.

Later you can rationalize -1/3√2.

Step-by-step explanation:

hope u like my answer. mark brainliest

Answer 2

Answer:

plz follow me and mark brainlist