Math, asked by sanskriti6106, 7 months ago

2x²-3√2+2=0 please answer​

Answers

Answered by Lurker3993
1

Answer:

3√2x²-5x-√2=0

3√2x²-(6-1)x -√2 = 0

3√2x²- 6x + x-√2=0

3√2x(x-√2)+1(x-√2) = 0

(x-√2)(3√2x+1) = 0

.•. x=√2 or x = -1/3√2

so the roots are √2 & -1/3√2.

Later you can rationalize -1/3√2.

Step-by-step explanation:

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Answered by neerajverma4151
1

Answer:

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