√2x²-3/√2x+1/√2=0 pls solve
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√2x^2 - 3x/√2 + 1/√2 = 0
Taking LCM and send denominator √2 to 0
2x^2 - 3x + 1 = 0
2x^2 -2x - x + 1 = 0
2x ( x - 1 ) -1 ( x - 1 ) = 0
( 2x - 1 ) ( x - 1 ) = 0
On comparing
2x - 1 = 0 => x = 1/2
x - 1 = 0 => x = 1
Taking LCM and send denominator √2 to 0
2x^2 - 3x + 1 = 0
2x^2 -2x - x + 1 = 0
2x ( x - 1 ) -1 ( x - 1 ) = 0
( 2x - 1 ) ( x - 1 ) = 0
On comparing
2x - 1 = 0 => x = 1/2
x - 1 = 0 => x = 1
Answered by
1
Answer:
X=1/2 X=1
Step-by-step explanation:
This answer is by quadratic formula
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