Question

2x²+3√2x-4=0 by factorization method

Answer 1

Answer:

x = -2√2 Or x = √2/2

Step-by-step explanation:

2x²+3√2x-4=0

Splitting the middle term, we get

=> 2x²+4√2x-√2x-4=0

=> 2x(x+2√2)-√2(x+2√2)=0

=> (x+2√2)(2x-√2)=0

=> x+2√2 = 0 Or 2x-√2 = 0

=> x = -2√2 Or 2x = √2

=> x = -2√2 Or x = √2/2

Therefore,

x = -2√2 Or x = √2/2

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Answer 2

$\large \underline{ \underline{ \sf \: Answer : \: \: \: }}$

$\to \sf x = \frac{1}{ \sqrt{2} } \: \: or \: \: x = - \frac{4}{ \sqrt{2} }$

$\large \underline{ \underline{ \sf \: Explaination : \: \: \: }}$

Splitting the middle term , we get

$\to \sf {2x}^{2} + 3 \sqrt{2} x - 4 = 0 \\ \\ \to \sf {2x}^{2} + 4 \sqrt{2}x - \sqrt{2}x - 4 = 0 \\ \\ \to \sf \sqrt{2} x( \sqrt{2} x + 4) - 1( \sqrt{2}x + 4) = 0 \\ \\ \to \sf (\sqrt{2} x - 1)( \sqrt{2}x + 4) = 0 \\ \\ \to \sf x = \frac{1}{ \sqrt{2} } \: \: or \: \: x = - \frac{4}{ \sqrt{2} }$