Question

(2x² – 3) + (4x² - 4) find ​

Answer 1

Step-by-step explanation:

$2 {x}^{2} + 4 {x}^{2} - 3 - 4 = 0$

$6 {x}^{2} - 7 = 0$

${x}^{2} = \frac{7}{6}$

$x = \sqrt{ \frac{7}{6} }$

Answer 2

Step-by-step explanation:

2x square+4x square −3−4=0

6x square-7 = 0

6x square = 7

x square = 7/6

taking both sides √

√x square = √7/6

so, x = √7/6