Question

2x2 +3 root3x+3 find its zeros​

Answer 1

$\displaystyle\sf{2x^2+3\sqrt3 x+3=0$

$\displaystyle\sf{x=\frac{-b \pm\sqrt{b^2-4ac}}{2a}$

$\displaystyle\sf{Here,$

• $\displaystyle\sf{a=2$

• $\displaystyle\sf{b=3\sqrt3$

• $\displaystyle\sf{c=3$

$\displaystyle\sf{x=\frac{-3\sqrt3\pm\sqrt{(3\sqrt3)^2-(4\times2\times3)}}{2\times2}$

$\displaystyle\sf{\implies x=\frac{-3\sqrt3\pm\sqrt{27-24}}{4}$

$\displaystyle\sf{\implies x= \frac{-3\sqrt3\pm\sqrt3}{4}$

$\displaystyle\sf{\implies x=\frac{-3\sqrt3+\sqrt3}{4}\:\:\:\:\:\:\:\:Or\:\:\:\:\:\implies x=\frac{-3\sqrt3-\sqrt3}{4}$

$\boxed{\displaystyle\sf{x=\frac{-\sqrt3}{2}\:\:\:\:\:\:\:\:Or\:\:\:\:\:x=-\sqrt3}}$