Question

-2x²+3x+2=0 , find roots​

Answer 1

Step-by-step explanation:

$\huge\underline{\underline{\sf ANSWER}} \\ - 2 {x}^{2} + 3x + 2 = 0 \\ \\ a = - 2 \: \\ b = 3 \\ c = 2 \\ \\ x = \frac{ - b + \: or \: - \sqrt{ {b}^{2} - 4ac } }{2a} \\ x = \frac{ - 3 + \: or \: - \sqrt{9 + 16} }{ - 4} \\ x = \frac{ - 3 + \: or \: - 5}{ - 4} \\ - 4x = - 8 \: \: \: \: or \: \: \: \: - 4x = 2 \\ x = 2 \: \: \: \: \: \: \: \: \: \: \: \: \: or \: \: \: \: x = - \frac{1}{2}$

Answer 2

Answer:

-2x^2+3x^2=x^2

x^2-x^2=0