Question

√2x² + 3x + √2
pls its urgent​

Answer 1

Answer:

$\sqrt{2} {x}^{2} + 3x + \sqrt{2}$

$= \sqrt{2} {x}^{2} + 2x + x + \sqrt{2}$

$= \sqrt{2} x(x + \sqrt{2} ) + 1(x + \sqrt{2} )$

$= (x + \sqrt{2} )( \sqrt{2} x + 1)$

Answer 2

Answer:

\sqrt{2} {x}^{2} + 3x + \sqrt{2}

2

x

2

+3x+

2

= \sqrt{2} {x}^{2} + 2x + x + \sqrt{2}=

2

x

2

+2x+x+

2

= \sqrt{2} x(x + \sqrt{2} ) + 1(x + \sqrt{2} )=

2

x(x+

2

)+1(x+

2

)

= (x +{2} {2} x + 1)=

(x+ 2 )( 2 x+1)

hope it helps you

thanku