√2x² +3x + √2 we have factorise it
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= √2x² +3x + √2
= √2x² + 2x + x + √2
= √2(x+√2 ) + 1(x+√2)
= (x+√2)(1+√2)
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√2x^2+3x +√2 = √2x^2 +2x+x +√2 = √2x(x+√2) + 1( x+√2) = (√2x+1)(x+√2), Hence factorised. If you want to find the value of x, then √2x+1=0 and x+√2=0 , √2x=-1 and x+√2=0. Now, we get x= -1/√2, -√2. Hope this helps you, if it helps you, mark me as Brainliest.
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