Question

2x2-3x+5=0 by factorisation method​

Answer 1

Answer:

Use the quadratic formula

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

2

2

−

3

+

5

=

0

2x^{2}-3x+5=0

2x2−3x+5=0

=

2

a={\color{#c92786}{2}}

a=2

=

−

3

b={\color{#e8710a}{-3}}

b=−3

=

5

c={\color{#129eaf}{5}}

c=5

=

−

(

−

3

)

±

(

−

3

)

2

−

4

⋅

2

⋅

5

√

2

⋅

2

x=\frac{-({\color{#e8710a}{-3}}) \pm \sqrt{({\color{#e8710a}{-3}})^{2}-4 \cdot {\color{#c92786}{2}} \cdot {\color{#129eaf}{5}}}}{2 \cdot {\color{#c92786}{2}}}

x=2⋅2−(−3)±(−3)2−4⋅2⋅5