Math, asked by rohithmk237, 4 months ago

2x²-3x-5=0 competing square

Answers

Answered by Toshal18

0

Answer:

Q) 2x^2-3x-5

= 2x^2+2x-5x-5

= 2x(x+1)-5(x+1)

= (2x-5) (x+1)

Here is your answer......

Answered by 000archana0

0

Answer:

{x}^{2} -3x=2.5

Step-by-step explanation:

plz mark me brilient

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