2x2-3x-5=0
The first number is supposed to be squared
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hey..
2x^2 - 3x - 5 = 0
divided by 2 as the coefficient of x^2 is 2
2x^2/2 - 3/2x - 5/2 = 0
x^2 -3/2x = 5/2
x^2 - 2(x)(3/4) + (3/4)^2 = 5/2 + (3/4)^2
(x - 3/4)^2 = 5/4 + 9/16
(x - 3/4)^2 = 20 + 9 / 16
underroot is *
x - 3/4 = *29/*16
x = *29/4 + 3/4
x = +*29 + 3 / 4 and x = -*29 + 3 / 4
2x^2 - 3x - 5 = 0
divided by 2 as the coefficient of x^2 is 2
2x^2/2 - 3/2x - 5/2 = 0
x^2 -3/2x = 5/2
x^2 - 2(x)(3/4) + (3/4)^2 = 5/2 + (3/4)^2
(x - 3/4)^2 = 5/4 + 9/16
(x - 3/4)^2 = 20 + 9 / 16
underroot is *
x - 3/4 = *29/*16
x = *29/4 + 3/4
x = +*29 + 3 / 4 and x = -*29 + 3 / 4
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