Question

2x2-3x+5 +3x2+3x-5
$2x2 - 3x + 5 + 3x2 + 3x - 5$
​

Answer 1

Answer:

1

Eliminate redundant parentheses

(

2

2

−

3

+

5

)

+

(

3

2

+

3

−

5

)

(2x^{2}-3x+5)+(3x^{2}+3x-5)

(2x2−3x+5)+(3x2+3x−5)

2

2

−

3

+

5

+

3

2

+

3

−

5

2x^{2}-3x+5+3x^{2}+3x-5

2x2−3x+5+3x2+3x−5

2

Subtract the numbers

2

2

−

3

+

5

+

3

2

+

3

−

5

2x^{2}-3x+{\color{#c92786}{5}}+3x^{2}+3x{\color{#c92786}{-5}}

2x2−3x+5+3x2+3x−5

2

2

−

3

+

3

2

+

3

2x^{2}-3x+3x^{2}+3x

2x2−3x+3x2+3x

3

Combine like terms

2

2

−

3

+

3

2

+

3

{\color{#c92786}{2x^{2}}}-3x+{\color{#c92786}{3x^{2}}}+3x

2x2−3x+3x2+3x

5

2

−

3

+

3

{\color{#c92786}{5x^{2}}}-3x+3x

5x2−3x+3x

4

Combine like terms

5

2

−

3

+

3

5x^{2}{\color{#c92786}{-3x}}+{\color{#c92786}{3x}}

5x2−3x+3x

5

2

5{\color{#c92786}{x^{2}}}

5x2

Solution

5

2

Answer 2

Concept Introduction: Addition of equations are easy.

Given:

We have been Given:

$(2 {x}^{2} - 3x + 5) + (3 {x}^{2} + 3x - 5)$

To Find:

We have to Find: Add the following.

Solution:

According to the problem, on addition we get,

$2 {x}^{2} + 3 {x}^{2} - 3x + 3x + 5 - 5 = 5 {x}^{2}$

Final Answer: The answer of the following is

$5 {x}^{2}$

#SPJ3