Question

2x²+3x-6=0 find the value of x
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Answer 1

Answer:

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Answer 2

Solution:

$\bigstar \: \: \sf{\underline{\boxed{\sf\large{2 {x}^{2} + 3x - 6 = 0}}} \: \: \bigstar}$

$\sf{Using \: Quadratic \: Formula:} \\\sf{ \frac{ - b \pm \sqrt{b^{2} - 4ac} }{2a} }$

$\sf:\implies{x = \dfrac{ - 3 \pm \sqrt{ {3}^{2}} - 4 \times 2( - 6)}{2 \times 2} }$

$\sf:\implies{x = {\dfrac{ - 3 \pm \sqrt{9 + 48} }{4}}}$

$\sf:\implies{x= \dfrac{ - 3 \pm \sqrt{57}}{4} }$

$\sf:\implies{}x ={ \underline{\boxed{\sf\dfrac{\sqrt{57} - 3}{4}}}=1.14(approx)}$

$\sf:\implies{}x ={ \underline{\boxed{\sf\dfrac{ - \sqrt{57} - 3}{4}}} = - 2.64(approx)}$

Hence, solved!