Question

2x²+3x+y² middle factorise this​

Answer 1

Step-by-step explanation:

2x² - xy - y² + 3x + 2y - 3 = 0. ...(1)

x² - 3x + 2 = 0. ...(2)

From equation (2),

x² - 3x + 2 = 0

or, x² - 2x - x + 2 = 0

or,. ( x - 2) ( x - 1 ) = 0

So, values of x are

x = 1, 2.

On putting the values of x in equation(1), we get

For x = 1, the value of y is

2(1)² - (1)y - y² + 3(1) + 2y - 3 = 0

- y² + y + 2 = 0

or,

y² - y - 2 = 0

y = (1±3)/2

On taking +ve sign,

y = 2

On -ve sign,

y = -1.

And for x = 2, the value of y is

2(4) - 2y - y² + 3(2) + 2y - 3 = 0

8 - y² + 6 - 3 = 0

or, y² = 11

or, y = ±√11

So, the values of x&y are

x = 1. y = -1, 2.

x = 2. y = ±√11

Answer 2

Answer:

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