Question

2x²(3xy+4x)+5y²(3z³+y³)​

Answer 1

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$\tt2x²(3xy+4x)+5y²(3z³+y³)$

$\tt6 {x}^{3} y + 8 {x}^{3} + 15 {y}^{2} {z}^{3} + 5 {y}^{4}$

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Answer 2

Answer:

❍ Solution :-

$\sf → {2x}^{2}(3xy + 4x) + {5y}^{2}({3z}^{3} + {y}^{3})$

➸ Mutlplying the terms,

$\sf → {2x}^{2}(3xy) + {2x}^{2}(4x) + {5y}^{2}({3z}^{3}) + {5y}^{2}({y}^{3})$

$\sf → 2{x}^{3}y + 8{x}^{3} + 15{y}^{2} {z}^{3} + 5{y}^{5}$

Hence, 2x²(3xy+4x)+5y²(3z³+y³) is equal to 2x³y + 8x³ + 15y²z³ + 5y⁴.