2x², -3y, 6y², -3x², –4y², 8y,From the pair of like terms, subtract the second term from the first term.
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4x,-3y,36x,
9x,-16y,8y
4x,-3y
9x,-16y
36x,8y
=49x,-11y
9x,-16y,8y
4x,-3y
9x,-16y
36x,8y
=49x,-11y
Answered by
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Solution :
*****************************************
Like terms :
Terms having the same literal
coeffients are called like terms .
******************************************
Given terms are 2x² , -3y , 6y² ,
-3x² , -4y² , 8y
i ) pair of like terms :
( 2x² , -3x² ),
( -3y , 8y ) ,
( 6y² , - 4y² )
ii ) Subtracting second term from
first in ( 2x² , -3x² ) we get
2x² - ( -3x² )
= 2x² + 3x²
= ( 2 + 3 )x²
= 5x²
iii ) Subtracting second term from
first in ( -3y , 8y ) we get
-3y - 8y
= ( -3 - 8 )y
= -11y
iv ) Subtracting second term from
first in ( 6y² , -4y² ) we get
6y² - ( -4y² )
= 6y² + 4y²
= ( 6 + 4 )y²
= 10y²
•••••
*****************************************
Like terms :
Terms having the same literal
coeffients are called like terms .
******************************************
Given terms are 2x² , -3y , 6y² ,
-3x² , -4y² , 8y
i ) pair of like terms :
( 2x² , -3x² ),
( -3y , 8y ) ,
( 6y² , - 4y² )
ii ) Subtracting second term from
first in ( 2x² , -3x² ) we get
2x² - ( -3x² )
= 2x² + 3x²
= ( 2 + 3 )x²
= 5x²
iii ) Subtracting second term from
first in ( -3y , 8y ) we get
-3y - 8y
= ( -3 - 8 )y
= -11y
iv ) Subtracting second term from
first in ( 6y² , -4y² ) we get
6y² - ( -4y² )
= 6y² + 4y²
= ( 6 + 4 )y²
= 10y²
•••••
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