Question

2x², –3y² ,+6z²,y², –2x², + z²,z² – 6x² –8y² and x² – y² answer me I algebraic adding do it fast​

Answer 1

Answer:

6y^2z^2−5x^2−12y^2+2z^2

Step-by-step explanation:

Because if you are adding all of these together then your initial equation would look like this

2x^2+-3y^2+6z^2y^2+-2x^2+z^2+z^2+-6x^2+-8y^2+x^2+-y^2 which would then combine all of the like terms which would then get you this equation

(6y^2z^2)+(2x^2+−2x^2+−6x^2+x^2)+(−3y^2+−8y^2+−y^2)+(z^2+z^2) which equals 6y^2z^2−5x^2−12y^2+2z^2

And please let me know if this helps.

Answer 2

Step-by-step explanation:

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To perform algebraic addition for the given expressions, we combine like terms.

2x² - 3y² + 6z² - 2x² + z² + z² - 6x² - 8y² + x² - y²

First, let's combine the like terms involving x²:

(2x² - 2x² - 6x² + x²) - 3y² + 6z² + (z² + z²) - 8y² - y²

Simplifying further:

-5x² - 11y² + 8z²

So the algebraic addition of the given expressions is -5x² - 11y² + 8z².

$\begin{gathered}\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\pmb{{More \: identities}}}} \\ \\ \bigstar \: \bf{ {(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} }\:\\ \\ \bigstar \: \bf{ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} }\:\\ \\ \bigstar \: \bf{ {x}^{2} - {y}^{2} = (x + y)(x - y)}\:\\ \\ \bigstar \: \bf{ {(x + y)}^{2} - {(x - y)}^{2} = 4xy}\:\\ \\ \bigstar \: \bf{ {(x + y)}^{2} + {(x - y)}^{2} = 2( {x}^{2} + {y}^{2})}\:\\ \\ \bigstar \: \bf{ {(x + y)}^{3} = {x}^{3} + {y}^{3} + 3xy(x + y)}\:\\ \\ \bigstar \: \bf{ {(x - y)}^{3} = {x}^{3} - {y}^{3} - 3xy(x - y) }\:\\ \\ \bigstar \: \bf{ {x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} )}\: \end{array} }}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

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