Question

2x² + 3y² ∝ xy , show that x+y ∝ x-y



plz give me the answer...
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Answer 1

Step-by-step explanation:

the question asks is how to find values of x and y such that the ratios x:y and 2x2+3y2:xy are equal.

That is equivalent to the equation x2y=2x2y+3y3 . y can’t be zero, so we can divide by y and rearrange to get

x2+3y2=0

which has no nonzero solutions in real numbers, which is usually the domain we’re talking about when ratios are involved. The ratio 0:0 is not well-defined so that isn’t a solution.

There are an infinite number of solutions y=±ix/√3 in complex numbers, for example x=i√3,y=1

x=(i3–√3)y

2x^2+3y^2

=−6+3

=−3

=(i√3)xy

Hope it helps you